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[list4xt] Re: How to pass node set to a template?

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Hi James,

James_Ma@i2.com wrote:
>
> Hi,
>
> In my xsl, I tried to pass node set to a template. The code looks
> like this:
>
> <xsl:template match="/">
>
> <xsl:variable name="taglib1">
> <xsl:apply-templates select="data_set/data"/>
> </xsl:variable>
>
> <xsl:call-template name="process_node_set">
> <xsl:with-param name="taglib"><xsl:value-of select="xt:node-set
> ($taglib1)"/></xsl:with-param>

To keep the status of "node set" to $taglib1, you should write:

<xsl:with-param name="taglib" select="xt:node-set($taglib1)"/>

(xsl:value-of is converting your node set to a string!)

> </xsl:call-template>
>
> </xsl:tempalte>
>
> <xsl:template name="process_node_set">
> <xsl:param name="taglib"></xsl:param>
> <xsl:apply-templates select="($taglib)"/>

This sould be :

  <xsl:apply-templates select="$taglib"/>

Hope this helps.

Eric

> </xsl:template>
>
> I got the following error when I processed the xml using above code:
> "SAXException: org.xml.sax.SAXException: cannot convert to node-set"
>
> Does anyone know how to pass node set to the template when using it?
>
> Appreciate any help/advise.
>
> -James
>

-- 
See you at XTech in San Diego.
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Eric van der Vlist       http://thepaymentguru.com -              http://collectionagencymerchantservices.com
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